My apologies and again to get to 20 characters!No you misunderstood me. I said that was a typo to your reply where I mistakenly said 100 n/m2 equates to 1 bar. As I said above 1 bar = 100,000 Pa or should have read 100,000 n/m2. It was late and I missed out some noughts.
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Brambles, can you please give me your calculated flow and resistance for the installed coil, preferably with the resistance in M.
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My own basic calcs would indicate that 5.8M of 22mm ID pipe should flow ~ 7.5 LPM @ 0.061M head which should satisfy the requirements except that the corrugations are having a huge effect but even if they do then there should be some reduced level of performance.
Ok, so for 22mm ID at 7.5lpm, that will equate to a velocity of around 0.33m/second.
If you run the two equations and consider the coil length is 8m. The minimum head required for the thermosyphon to operate at that velocity is 2.4 inches of water or 0.061m of water.
This may be on the low side depending on the friction factor if the pipe coil is corrugated on the inside.
The above only calculates the force required to drive the flow at 7.5lpm through the coil - it does not allow for the interconnecting pipework.
As stated earlier, for a 28mm dia coil at the same velocity, the force required is significantly lower
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